Question

решите уравнение 3*2^x-3+2^x=22​

Answer 1

3·2ˣ-3+2ˣ = 22

4·2ˣ = 22+3 = 25

2ˣ = 25:4 = 6,25

$x=\log_2{6,\! 25}$

Или

$\displaystyle 3\cdot 2^{x-3} +2^x=22\\\\\dfrac38 \cdot 2^x+2^x=22\\\\2^x=22:\dfrac{11}{8} =2^4$

x = 4