Предмет: Алгебра, автор: andruen1337

В копилке было 18 монет по 2 рубля и по 5 рублей, на сумму 45 рублей. Сколько монет каждого вида (решение надо системой уравнений)

Ответы

Автор ответа: ysupertulia
1

Ответ:

первое уравнение x+y=18

второе уравнение 2x+5y=45

выразим x из первого уравнения и подставим его значение во второе x=18-y

2(18-y)+5y=45

36-2y+5y=45

3y=9. y=3

найдем x подставив найденное значение y в первое уравнение x=18-3=15


ysupertulia: забыла написать, что за x приняли количество монет по2 рубля, за y количество монет по 5 руб
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