Question

Допоможіть будь ласка.

Answer 1

Ответ:

1)  $\frac{2x^{2}+5x-3 }{3x^{2}+10x+3} =\frac{2x^{2}+6x-x-3 }{3x^{2}+9x+x+3 }=\frac{2x*(x+3)-(x+3)}{3x*(x+3)+x+3}=\frac{(x+3)*(2x-1)}{(x+3)*(3x+1)} =\frac{2x-1}{3x+1}$

2)$\frac{3x^{2} -5x-2}{2x^{2}-5+2 }=\frac{3x^{2}-x-6x-2 }{2x^{2}-x-4x+2 } =\frac{x(3x+1)-2(3x+1)}{x(2x-1)-2(2x-1)} =\frac{(3x+1)(x-2)}{(2x-1)(x-2)}=\frac{3x+1}{2x-1}$