Question

СРОЧНО!!! 25 БАЛЛОВ.

Answer 1

$\left\{\begin{array}{l}\dfrac{2-2x}{8+(2-6x)^2}\geq 0\\5-9x\leq 37-5x\end{array}\right\\\\\\a)\; \; \dfrac{2-2x}{8+(2-6x)^2}\geq 0\; \; \; \Rightarrow \; \; \; 2-2x\geq 0\; \; ,\; \; tak\; kak\\\\(2-6x)^2\geq 0\; \; \Rightarrow \; \; \; 8+(2-6x)^2\geq 8>0\; ,\\\\2\geq 2x\; \; ,\; \; 2x\leq 2\; \; ,\; \; x\leq 1\\\\b)\; \; 5-9x\leq 37-5x\; \; \Rightarrow \; \; \; 5-37\leq 9x-5x\; \; ,\; \; -32\leq 4x\; \; ,\; \; 4x\geq -32\\\\x\geq -8$

$c)\; \; \left\{\begin{array}{l}x\leq 1\\x\geq -8\end{array}\right\; \; \; \ \ \ \Rightarrow \ \ \; \; \; -8\leq x\leq 1\\\\\\Otvet:\; \; x\in [-8\, ;\; 1\; ]\; .$