Question

Срочно нужно решить даю 60 балов

Answer 1

$x^{2}$ + 4x = -3x - 10

$x^{2}$ + 4x + 3x + 10 = 0

$x^{2}$ + 7 x + 10 = 0

D = $b^{2}$ - 4ac = 7^2 - 4 × 1 × 10 = 49 - 40 = 9

$\sqrt{D}$ = $\sqrt{9}$ = 3

$x_{1}$ = $\frac{-b-\sqrt{D} }{2a}$ = $\frac{-7 - 3}{2}$ = -5

$x_{2}$ = $\frac{-b+ \sqrt{D} }{2a}$ = $\frac{-7+3}{2}$ = -2

Ответ: -5; -2