Question

система 3×(x-2)-2×(y+1)=-1 5×(x+3)-8×(y-2)45​

Answer 1

Ответ:$x=2, y=-\frac{1}{2}$

Объяснение:

$\left \{ {3*(x-2)-2*(y+1)=-1{} \atop {5*(x+3)-8*(y-2)=45} \right. \\\left \{ {{x=\frac{7}{3}+\frac{2}{3}y } \atop {5(x+3)-8(y-2)=45}} \right.\\5(\frac{7}{3} +\frac{2}{3} y+3)-8(y-2)=45\\5(\frac{16}{3} +\frac{2}{3} y)-8y+16=45\\\frac{80}{3} +\frac{10}{3} -8y+16=45\\\frac{128}{3} -\frac{14}{3} =45\\128-14y=135\\-14y=135-128\\-14y=7\\y=-\frac{1}{2} \\x=\frac{7}{3} +\frac{2}{3} *(-\frac{1}{2} )\\x=2$