Question

сократите дробь
ᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠᅠ​

Answer 1

$\dfrac{3x^2-27}{3x-x^2} =\dfrac{3(x^2-3^2)}{x(3-x)} =\\\\=\dfrac{3(x-3)(x+3)}{-x(x-3)} =-\dfrac{3x+9}x$