Question

Дам 25 б
Реши уравнение:
11y2+33y−(y+3)=0.

Корни уравнения
y1=
y2=

Answer 1

$11y^2+33y-(y+3)=0\\11y^2+33y-y-3=0\\11y(y+3)-(y+3)=0\\(y+3)(11y-1)=0\\y+3=0\\11y-1=0\\y_1= -3\\y_2= \frac{1}{11}$