Question

сократите дробь: 
6а^2+11a+3 / 3+5a-12a^2

Answer 1

$frac{6a^2+11a+3}{3+5a-12a^2};$
$D=121-72=49; x_1=- frac{1}{3};x_2=- frac{3}{2};$
$D=25+144=169;x_1= frac{3}{4};x_2=- frac{1}{3}.$
 $frac{6a^2+11a+3}{3+5a-12a^2}= frac{(3x+1)(2x+3)}{-(4x-3)(3x+1)} =- frac{2x+3}{4x-3}$