Question

определите массовю доли элементов в вещетвах Zn(OH)2

Answer 1

Ответ:

Объяснение:

Zn(OH)₂

Mr(Zn(OH)₂) = 65 + 2*1 + 16*2 = 99

$w(Zn) = \frac{Ar(Zn)}{Mr(Zn(OH)_{2}} *100 = \frac{65}{99}*100 = 65.7%$

$w(H) = \frac{2*Ar(H)}{Mr(Zn(OH)_{2}} * 100 = \frac{2*1}{99} *100 = 2%$

$w(O) = \frac{2*Ar(O)}{Mr(Zn(OH)_{2}} * 100% = \frac{2*16}{99} * 100 = 32.3$ = 32.3%

Ответ: w(Zn) = 65.7%; w(H) = 2%; w(O) = 32.3%