Предмет: Алгебра, автор: brawlststars234

Розв'яжіть біквадратне рівняння х⁴ - 26x² + 25 = 0.

Ответы

Автор ответа: wnull

Имеем

$x^4-26x^2+25=0\\$

Решаем уравнение методом замены

$x^2=t$

Решнеие

$t^2-26t+25=0\\t_1=1\\t_2=25$

Подставляем обратно

$x^2=1\\x^2=25$

Корни

$x_1=-5\\x_2=-1\\x_3=1\\x_4=5$

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Розв'яжіть біквадратне рівняння х⁴ - 26x² + 25 = 0.​

Ответы

Розв'яжіть біквадратне рівняння х⁴ - 26x² + 25 = 0.