Question

Решите систему неравенств

2-5x<4(1-x)

4-x/2>2x

Answer 1

$\left\{\begin{array}{l}2-5x<4\, (1-x)\\4-\frac{x}{2}>2x\end{array}\right\; \; \left\{\begin{array}{l}2-5x<4-4x\\8-x>4x\end{array}\right\; \; \left\{\begin{array}{l}2-4<5x-4x\\8>4x+x\end{array}\right\\\\\\\left\{\begin{array}{l}-2<x\\8>5x\end{array}\right\; \; \left\{\begin{array}{l}x>-2\\5x<8\end{array}\right\; \; \left\{\begin{array}{l}x>-2\\x<1,6\end{array}\right\; \; \; \Rightarrow \; \; \; -2<x<1,6\\\\\\x\in (\, -2\; ;\; 1,6\, )$