Question

x3+125y3 1-27y3 0.001x3-8y3 x3y9+343

Answer 1

1) $x^{3}+125y^{3}=(x)^{3}+(5y)^{3}=(x+5)(x^{2}-5x+25)$

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2) $1-27y^{3}=(1)^{3}-(3y)^{3}=(1-3y)(1+3y+9y^{2})$

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3) $0,001x^{3}-8y^{3}=(0,1x)^{3}-(2y)^{3}=(0,1x-2y)(0,01x^{2}+0,2xy+4y^{2})$

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4) $x^{3}y^{9}+343=(xy^{3})^{3}+(7)^{3}=(xy^{3}+7)(x^{2}y^{6}-7xy^{3}+49)$