Question

срочно даю 45 баллов!!!!!

Answer 1

Ответ:108

Объяснение:

Answer 2

$x^2+10x-4=0\; \; \Rightarrow \qquad \left\{\begin{array}{l}x_1+x_2=-10\\x_1\cdot x_2=-4\end{array}\right\quad (teorema\; Vieta)\\\\\\(x_1+x_2)^2=(-10)^2\\\\x_1^2+2x_1x_2+x_2^2=100\\\\x_1^2+2\cdot (-4)+x_2^2=100\\\\x_1^2+x_2^2=100+8\\\\\boxed {\; x_1^2+x_2^2=108\; }$