Question

помогите с заданием пожалуйста

Answer 1

$f(x)=0,5\, sin(2x+\dfrac{\pi}{6})\; \; ,\; \; x_0=\frac{\pi}{12}\\\\f'(x)=0,5\cdot cos(2x+\dfrac{\pi}{6})\cdot 2=cos(2x+\dfrac{\pi}{6})\\\\f'(\dfrac{\pi}{12})=cos(\dfrac{\pi}{6}+\dfrac{\pi}{6})=cos\dfrac{\pi}{3}=\dfrac{1}{2}$