Question

11x^2-9x+1=0 хелпаните плс

Answer 1

Объяснение:

$11x {}^{2} - 9x + 1 = 0$

$d = 81 - 44 = 37$

$x1 = 9 + \sqrt{37} \div 22$

$x2 = 9 - \sqrt{37} \div 22$

Answer 2

$11x^2-9x+1=0\\\\D=81-44=37\\\\x_1=\dfrac{9-\sqrt{37}}{22}\; \; ,\; \; \; x_2=\dfrac{9+\sqrt{37}}{22}$