Question

Решите неравенство X^2-8x+12<0

Answer 1

Ответ:

$x {}^{2} - 8x + 12 > 0$

$x { }^{2} - 2x - 6x + 12 < 0$

$x \times (x - 2) - 6(x - 2) < 0$

$(x - 2) \times (x - 6) < 0$

${x < 2$

${x > 6$

Х є [2; 6]