Question

помогите пожалуйста, если можно розпишите пожалуйста)))​

Answer 1

$1.\\x+3=10 => x = 7\\2. 48:x = 6 => x = 8\\2.\\m^5m^4 = m^9\\p^7:p^2 = p^5\\3.\\K(10;-1) => 10 - 1 = 9\\F(5;6) => 5 + 6 = 11\\4.\\(x-4)(x+4)-x(x-5) = x^2 - 16 - x^2 + 5x = 5x - 16\\(c+3)^2 + (c-7)(c+1) = c^2 + 6c + 9 - c^2 - 6c - 7 = 2$