Предмет: Физика, автор: mirzebekovaludmilann

меньшая сила ,действующая на рычаг, равна 5000мН. найдите большую силу,если плечи рычага 0,1м и 0,3м

Ответы

Автор ответа: btsbts1
1

Ответ:

F1/F2 = l2/l1

F2 = l1/l2F1

F2 = 0,3 м/0,1 м ⋅ 5 Н = 15 Н

Ответ:

F2 = 15 Н

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