Предмет: Алгебра, автор: hdgsreiszsjw

Помогите пожалуйста срочно!!!
Метод интервалов
2х²х−4 > −324−х

Ответы

Автор ответа: torrimandarinka
1

Ответ:

2х²-4>-х-324

2х²-4+х+324>0

2х²+х+320>0

Решим квадратное уравнение

2х²+х+320=0

Корней нет,

Т.к. а=2>0, то 2х²+х+320>0 для любых х

Ответ: х∈R или х - любое число

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