Question

Сократите дробь 4a^2+a-3/a^2-a-2

Answer 1

$\frac{4a^2+a-3}{a^2-a-2} = \frac{\left(4a^2-3a\right)+\left(4a-3\right)}{\left(a^2+a\right)+\left(-2a-2\right)} = \frac{a\left(4a-3\right)+\left(4a-3\right)}{a\left(a+1\right)-2\left(a+1\right)} = \frac{\left(4a-3\right)\left(a+1\right)}{\left(a+1\right)\left(a-2\right)} = \frac{4a-3}{a-2}$