Question

помагите пожалуйста 2 и 4 ​

Answer 1

2) 3$\frac{5}{12}$ + 9$\frac{1}{6}$ - 5$\frac{1}{18}$ = $\frac{41}{12}$ + $\frac{55}{6}$ - $\frac{91}{18}$ = $\frac{123 + 330 - 182}{36}$ = $\frac{271}{36}$ = 7$\frac{19}{36}$

4) 5$\frac{2}{3}$ + 11$\frac{7}{12}$ - 4$\frac{3}{4}$ = $\frac{17}{3}$ + $\frac{139}{12}$ - $\frac{19}{4}$ = $\frac{68 + 139 - 57}{12}$ = $\frac{150}{12}$ = 12$\frac{6}{12}$ = 12$\frac{1}{2}$ = 12,5