Question

Помогите пожалуйста с решением!!!

Answer 1

Ответ:

$\frac{x(x + 1)}{(x - 1)(x + 1)} - \frac{5(x - 1)}{(x - 1)(x + 1)} - \frac{2}{(x - 1)(x + 1) }$

$\frac{{x}^{2} + x - 5x + 5 - 2}{(x - 1)(x + 1)}$

$\frac{ {x}^{2} - 4x + 3 }{(x - 1)(x + 1)}$

${x}^{2} - 4x + 3 = 0 \\ (x - 1)(x + 1) = 0$

1 дискриминант

Answer 2

$\dfrac{x}{x-1}-\dfrac{5}{x+1}=\dfrac{2}{x^2-1}\; \; ,\; \; \; \; ODZ:\; \; x\ne \pm 1\\\\\\\dfrac{x(x+1)-5(x-1)}{(x-1)(x+1)}=\dfrac{2}{(x-1)(x+1)}\\\\\\\dfrac{x(x+1)-5(x-1)-2}{(x-1)(x+1)}=0\\\\\\\dfrac{x^2-4x+3}{(x-1)(x+1)}=0\; \; \; \to \; \; \; \left\{\begin{array}{ccc}x^2-4x+3=0\\(x-1)(x+1)\ne 0\end{array}\right\; \; \left\{\begin{array}{ccc}x_1=1\; ,\; x_2=3\\x\ne -1\; ,\; x\ne 1\end{array}\right\\\\\\Otvet:\; \; x=3\; .$