Question

Решите уравнение 4)8/3-x=20/4+x

Answer 1

$\frac{8}{3-x} =\frac{20}{4+x} \\\\\frac{8(4+x)}{3-x} =20\\\\8(4+x)=20(3-x)\\\\32+8x=60-20x\\\\8x+20x=60-32\\\\28x=28\\\\x=28:28\\\\x=1$