Question

1342. Спасите кто нибудь ​

Answer 1

$\displaystyle \left \{ {{\dfrac{3x - 1}{2} + \dfrac{9 - 5y}{3} = 2,5 \ \ \ \ \ | \cdot 6 \ \ } \atop {\dfrac{8 - 3y}{4} - \dfrac{6 + 5x}{3} = 0 \ \ \ \ \ \ \ | \cdot 12 }} \right.$

$\displaystyle \left \{ {{3(3x - 1) + 2(9 - 5y) = 15} \atop {3(8 - 3y) - 4(6 + 5x) = 0 \ }} \right.$

$\displaystyle \left \{ {{9x - 3 + 18 - 10y = 15} \atop {24 - 9y - 24 - 20x = 0}} \right.$

$\displaystyle \left \{ {{9x - 10y = 0 \ \ \ \ \ \ | \cdot 20} \atop {-20x - 9y = 0 \ \ \ | \cdot 9 \ \ }} \right.$

$+ \displaystyle \left \{ {{180x - 200 y = 0} \atop {-180x - 81y = 0}} \right.$

$-281y = 0\\y = 0$

$9x - 10 \cdot 0 = 0\\x = 0$

Ответ: (0; 0).