Question

12 inhaber
1/(t+x)(m+y); Buranoūmeumssicemente
Danama probna
2)(x-4) (p+1); upona und MSC ME
3)(y - 3)(4+7);​ ПОМОГИТЕ РЕШИТЬ

Answer 1

Ответ:

1) (t+x)(m+y) = tm+xm+ty+xy

2) (x-4)(p+1) = xp-4p+x-4

3) (y - 3)(4+7) = 4y-12+7y-21 =4y+7y-33