Question

Даю 20 баллов срочно надо​

Answer 1

Ответ:

Объяснение:

A. 2,5*2⁴-7²=2,5*16-49=40-49=-9.

$B.(-1\frac{1}{3} )^{2} +(\frac{1}{2})^{3}-(\frac{5}{19})^{0}+(-1)^{8}=(-\frac{4}{3})^{2}+\frac{1}{8} -1+1=\\ =-\frac{16}{9}+\frac{1}{8}= \frac{-16*8+9}{72} =\frac{-128+9}{72} =-\frac{119}{72} =-1\frac{47}{72} .$

$C.\frac{3^{10}*27^{3} }{9^{9} } =\frac{3^{10}*(3^{3})^{3} }{(3^{2})^{9} } =\frac{3^{10}*3^{9} }{3^{18} } =\frac{3^{19} }{3^{18} } =3.\\D.(5\frac{1}{3})^{7} *(\frac{3}{16} )^{8}=(\frac{16}{3})^{7} *(\frac{3}{16})^{8} =(\frac{16}{3})^{7} *(\frac{3}{16})^{7}*\frac{3}{16} =\frac{3}{16} .$