Question

Решите уравнение: (x-5)^2+2(x-5)-63=0

Answer 1

(х^2-2*5х+25)+2х-2*5-63=0

х^2-10х+25+2х-10-63=0

х^2-8х-48=0

Д=b^2-4ac=8^2-4*1*(-48)=64+192=256=16^2

x1=(8+16)/2=12

х2=(8-16)/2=-4

Answer 2

x^2-10x+25+2x-10-63=0

x^2-8x-48=0

D=64+192=256

x=(8-+16)/2

x1=-4 x2= 12