Question

Решить производные
(x+sin x)'=x'+(sin x)'=1+cos x

(x+tgx)'=

(8-15x)'=

((-2)*(6x-3))=

(x-2/6x-3)=

Answer 1

(x+sin x)'=x'+(sin x)'=1+cos x

(x+tgx)'=x'+(tgx)'=1+(1/cos²x)

(8-15x)'=0-15

((-2)*(6x-3))'=-6*(2x-1)'=-6*2=-12

((x-2)/(6x-3))'=((x-2)'*(6x-3)-(x-2)*(6x-3)')/(6x-3)²=(6x-3-6x+12)/(6x-3)²=

9/(6x-3)²