Question

Помогите решить :)))​

Answer 1

$2^{5-x}=4,5\cdot 9^{5-x}\\\\\dfrac{2^{5-x}}{9^{5-x}}=\dfrac{9}{2}\; \; \; ,\; \; \; \; \Big(\dfrac{2}{9}\Big)^{5-x}=\dfrac{9}{2}\; \; \; ,\; \; \; \Big(\dfrac{9}{2}\Big)^{x-5}=\dfrac{9}{2}\\\\\\x-5=1\\\\\boxed {\; x=6\; }$