Question

$\frac{ {17x}^{ - 8} }{ {14y}^{ - 12} } \times \frac{ {28y}^{} }{ {51x}^{ - 21} } =$

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Answer 1

$\frac{ {17x}^{ - 8} }{ {14y}^{ - 12} } \times \frac{ {28y}^{} }{ {51x}^{ - 21} } = \frac{{17x}^{ - 8} \times28y }{{14y}^{ - 12} \times {51x}^{ - 21}} = \frac{1 \times 2}{1 \times 3} x { }^{ - 8 - ( - 12)} y {}^{1 - ( - 12)} = \frac{2}{3} x {}^{ - 8 + 12} y {}^{1 + 12} = \frac{2x {}^{13} y {}^{13} }{3}$