Question

Помогите решить пример

Answer 1

$\frac{6}{x^{2}-1}+\frac{3}{x+1}=\frac{x+1}{x-1}\\\\\frac{6}{(x-1)(x+1)}+\frac{3}{x+1}-\frac{x+1}{x-1}=0\\\\\frac{6+3x-3-x^{2}-2x-1 }{(x-1)(x+1)} =0\\\\\frac{x^{2}-x-2 }{(x-1)(x+1)}=0\\\\x-1\neq0\Rightarrow x\neq1\\\\x+1\neq0\Rightarrow x\neq-1\\\\x^{2} -x-2=0\\\\x_{1}=2\\\\x_{2}=-1-neyd\\\\Otvet:\boxed{2}$