Question

(0,2x-3)^2-36=0 помогите решить

Answer 1

(0,2x-3)^2-36=0

a² - b² = (a - b)(a + b)

(0,2x-3)^2-6^2=0

(0.2x - 3 - 6)(0.2x - 3 + 6) = 0

(0.2x - 9)(0.2x + 3) = 0

0.2x = 9

x = 45

0,2x = -3

x = -15

ответ -15 и 45