Question

(4^x)+(2^x+3) = 20 С РЕШЕНИЕМ
ПОМОГИТЕ, ПОЖАЛУЙСТА!!!!!!!!!!!!!!

Answer 1

$4^{x}+2^{x+3}=20\\\\(2^{x})^{2}+2^{x}*2^{3} -20=0\\\\(2^{x})^{2}+8*2^{x}-20=0\\\\2^{x}=m,m>0\\\\m^{2}+8m-20=0\\\\m_{1}=2\\\\m_{2}=-10<0-neyd\\\\2^{x}=2\\\\x=1$