Question

хелп с алгеброй даю 15 балов

Answer 1

Ответ:

Объяснение:

$\frac{3x-9x^{2} }{x^{2}+6x+9 } :\frac{1-9x^{2} }{x^{2} -9}=\frac{3x*(1-3x)}{(x+3)^{2} } *\frac{x^{2}-9 }{1-9x^{2} } =\frac{3x*(1-3x)*(x+3)*(x-3)}{(x+3)^{2}*(1-3x)*(1+3x) } =\frac{3x*(x-3)}{(x+3)*(1+3x)}=\\ =\frac{3*1*(1-3)}{(1+3)*(1+3*1)}=\frac{3*(-2)}{4*4} =-\frac{3}{8}.$