Question

Плз помогите
4х^4-5х^2+1=0

Answer 1

Ответ:

$4 {x}^{4} - 5 {x}^{2} + 1 = 0 \\ {x}^{2} = t \\ 4{t}^{2} - 5t + 1 = 0 \\ d = 25 - 4 \times 4 = 9 \\ t1 = \frac{5 - 3}{2 \times 4} = \frac{1}{4} \\ t2 = \frac{5 + 3}{8} = 1 \\ {x}^{2} = \frac{1}{4} \\ x = + - \frac{1}{2} \\ {x}^{2} = 1 \\ x = + - 1$