Question

Найдите корни уравнения 
1)(2x-1)(3x+4)-6x во 2-ой =16
2)(1-2y)(1-3y)=(6y-1)y-1
3)7+2x во 2-ой=2(x+1)(x+3)
4)(y+4)(y+1)=y-(y-2)(2-y)

Answer 1

6x^2 - 3x + 8x -4 - 6x^2 = 16 (6x^2 - 6x^2) + (8x - 3x) = 16+45x = 20x = 4