Question

Выполните действие:
$\frac{2xy^{2} }{3x-y} : \frac{xy^{3} }{9x^{2}-y^{2} } * \frac{2y}{3x+y}$

Answer 1

$\frac{2x {y}^{2} }{3x - y} \times \frac{9x { }^{2} - y {}^{2} }{xy {}^{3} } \times \frac{2y}{3x + y}$

$\frac{2}{3x - y} \times \frac{(3x - y) \times (3x + y)}{y} \times \frac{2y}{3x + y}$

$2 \times 1 \times 2$

$4$