Question

4y^2/x2-2xy - x/x-2y​

Answer 1

$\frac{4y^2}{x^2-2xy}-\frac{x}{x-2y} =\\\\=\frac{4y^2}{x\left(x-2y\right)}-\frac{x}{x-2y} =\\\\=\frac{4y^2}{x\left(x-2y\right)}-\frac{x^2}{x\left(x-2y\right)}=\\\\=\frac{4y^2-x^2}{x\left(x-2y\right)}=\\\\=\frac{\left(2y+x\right)\left(2y-x\right)}{x\left(x-2y\right)}=\\\\=-\frac{2y+x}{x}$

Answer 2

Пошаговое объяснение:

4y^2/x^2-2xy - x/x-2y=

4y^2/x^2-2xy - x*x/(x-2y)*x=

(2y)^2 - x^2 /x^2 - 2xy=

(2 y-x) (2 y+x) /x(x-2 y) = - 2y-x/x