Question

решите систему неравенств

Answer 1

$\left\{\begin{array}{l} x^2-x-2 \; \textless \; 0 \\ 5-2x\geq 0 \end{array}\right \Rightarrow\; \left \{ \begin{array}{l} (x+1)(x-2) \; \textless \; 0 \\ x \leq \frac{5}{2} \end{array}\right \Rightarrow\; \left \{ \begin{array}{l} -1 \; \textless \; x \; \textless \; 2 \\ x \leq 2.5 \end{array}\right\;\; \Rightarrow \\\\\\-1 \; \textless \; x \; \textless \; 2\; \; \; ,\; \; \; x\in (-1\;;\;2).$