Question

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Выполните действия:
14x-9/17x+3x-25/17x=

ax+ay/xy^3*x^3y/8x+8y=

$\frac{14x - 9}{17x} + \frac{3x - 25} {17x} =$

$\frac{ax + ay}{xy {}^{3} } \times \frac{x {}^{3}y }{8x + 8y} =$
​

Answer 1

$\frac{14x - 9}{17x} + \frac{3x - 25}</p><p>{17x} = \frac{14x - 9 + 3x - 25}{17x} = \frac{17x - 34}{17 x} = \frac{17(x - 2)}{17x} = \frac{x - 2}{x}$

$\frac{ax + ay}{xy {}^{3} } \times \frac{x {}^{3}y }{8x + 8y} = \frac{a(x + y) \times x {}^{3} y}{xy {}^{3} \times 8(x + y) } = \frac{a {x}^{2} }{8 {y}^{2} }$