Question

Помогите решить математику ПЖЖ"!!!!

Answer 1

$y' = \left(\dfrac{4}{3 + x^{3}} \right)' = -4 \cdot \dfrac{(3 + x^{3})'}{(3 + x^{3})^{2}} = -\dfrac{12x^{2}}{(3 + x^{3})^{2}}$

$y'(2) = -\dfrac{12\cdot 2^{2}}{(3 + 2^{3})^{2}} = -\dfrac{12\cdot 4}{(3 + 8)^{2}} = -\dfrac{48}{121} \approx -0,40$