Question

1. $\sqrt{15}^{(4-log_{15}9)}$

2. $\left( 2^{log_2(\sqrt{5}-2)} + 3^{log_9(\sqrt{5}+2)^2} \right)^2$

Answer 1

решение прикреплено в фото

Answer 2

$1)\sqrt{15}^{(4-log_{15}9)}=(15^{\frac{1}{2}})^{4-log_{15}9}=15^{2-log_{15}3}=15^{2}*15^{log_{15}\frac{1}{3}}=225*\frac{1}{3}=75\\\\2)(2^{log_{2}(\sqrt{5}-2)}+3^{log_{9}(\sqrt{5}+2)^{2}} )^{2}=(\sqrt{5}-2+3^{log_{3}(\sqrt{5}+2)})^{2} =(\sqrt{5}-2+\sqrt{5}+2)^{2}=(2\sqrt{5})^{2}=20$