Question

Помогите с алгеброй, номер 2

Answer 1

$\frac{2Cos\alpha+Sin\alpha}{Cos\alpha-2Sin\alpha}=\frac{\frac{2Cos\alpha}{Sin\alpha}+\frac{Sin\alpha}{Sin\alpha}}{\frac{Cos\alpha}{Sin\alpha}-\frac{2Sin\alpha }{Sin\alpha}}=\frac{2Ctg\alpha+1}{Ctg\alpha-2 }=\frac{2*\frac{13}{4}+1 }{\frac{13}{4}-2}=\frac{6,5+1}{3,25-2} =\frac{7,5}{1,25}=6$