Question

решите уравнение (2400:(25х+175):6+58):20=3 ((120+х)·100:2+200):250:25=1

Answer 1

(2400:(25х+175):6+58):20=3,
(2400:(25х+175):6+58=60,
(2400:(25х+175):6=2,
(2400:(25х+175)=12,
25х+175=200,
25х=25,
х=1.

((120+х)·100:2+200):250:25=1,
((120+х)*100:2+200):250=25,
(120+х)*100:2+200=6250,
(120+х)*100:2=6050,
(120+х)*100=12100,
120+х=121,
х=1.