Question

Помогите пж с алгеброй)))

Answer 1

$\frac{3}{z - 2} + \frac{7}{z + 2} = \frac{10}{z} \\ \frac{3(z + 2) + 7(z - 2)}{(z - 2)(z + 2)} = \frac{10}{z} \\ 10(z {}^{2} - 4) = z(3z + 6 + 7z - 14) \\ 10z {}^{2} - 40 =z(10z - 8) \\ 10 {z}^{2} - 40 = 10 {z}^{2} - 8z \\ 10z {}^{2} - 10z {}^{2} + 8z = 40 \\ 8z = 40 \\ z = \frac{40}{8} \\ z = 5$