Question

Помогите, решить данные уравнения

Answer 1

$\sqrt[3]{ - 27} = - \sqrt[3]{(3) {}^{3} } = - 3$

$\sqrt[4]{81} = \sqrt[4]{(3) {}^{4} } = 3$

$\sqrt[5]{ - 32} = - \sqrt[5]{(2) {}^{5} } = - 2$

$\sqrt[3]{64} = \sqrt[3]{(4) {}^{3} } = 4$

$\sqrt[5]{ \frac{1}{32} } = \frac{ \sqrt[5]{1} }{ \sqrt[5]{(2) {}^{5} } } = \frac{1}{2} = 0.5$

$\sqrt[4]{ \frac{81}{625} } = \frac{ \sqrt[4]{(3) {}^{4} } }{ \sqrt[4]{(5) {}^{4} } } = \frac{3}{5} = 0.6$

$\sqrt[3]{ - \frac{27}{8} } = - \frac{ \sqrt[3]{(3) {}^{3} } }{ \sqrt[3]{(2) {}^{3} } } = - \frac{3}{2} = - 1.5$

$\sqrt[4]{ \frac{81}{256} } = \frac{ \sqrt[4]{(3) {}^{4} } }{ \sqrt[4]{(4) {}^{4} } } = \frac{3}{4} = 0.75$

$( - \sqrt[4]{ 11} ) {}^{4} = 11$

$(2 \sqrt[5]{ - 2} ) {}^{5} = ( - 2 \sqrt[5]{2} ) {}^{5} = - 32 \times 2 = - 64$

$( \sqrt[3]{7} ) {}^{3} = 7$

$( - \sqrt[6]{2} ) {}^{6} = 2$