Question

Розкласти на множники квадратний тричлен.-x2-4x+5

Answer 1

$- x {}^{2} - 4x + 5 = - {x}^{2} + x - 5x + 5 =( - {x}^{2} + x ) + (- 5x + 5) = - x(x - 1) - 5(x - 1) = (x - 1)( - x - 5) = - (x - 1)(x + 5)$