Предмет: Геометрия, автор: leonidkovalev2017

Дано: ΔBAC,CB=CA.
Боковая сторона треугольника в 4 раз(-а) больше его основания.
Периметр треугольника BAC равен 90 дм.
Вычисли стороны треугольника.

BA=
;

CB=
;

CA=
.

Ответы

Автор ответа: Alyssa08
2

Дано:

△BCA - равнобедренный.

CB = CA.

AB > в 4 раза, чем CB.

P = 90 дм.

Найти:

CB; AB; CA.

Решение:

Пусть x дм - AB, тогда 4x дм - CB, CA (т.к. боковые стороны равны)

Периметр равен 90 дм.

Составление математической модели.

x + 4x + 4x = 90

Работа с математической моделью

9x = 90

x = 10

10 дм. - AB

CB = CA = 10 * 4 = 40 дм.

Ответ: 10 дм; 40 дм; 40 дм.

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