Предмет: Физика, автор: chaleksv

При равновесии на большее плечо рычага действует сила 60 ньютон на меньшее плечо 120 ньютон большее плечо равно 20 см длина меньшего плеча становится
надо узнать длину меньшего рычага

Ответы

Автор ответа: DedStar

Ответ:

Объяснение:

Дано:

F₂ = 60 Н

d₂ = 20 см = 0,20 м

F₁ = 120 Н

_____________

d₁ - ?

По правилу рычага:

F₁·d₁ = F₂·d₂

d₁ = F₂·d₂ / F₁

d₁ = 60·0,0,20 / 120 = 0,10 м или 10 см

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